` int _(0)^(pi/2) ((root(n)secx)/(root(n) ( secx+ root(n)"cosec"x)))dx` is equal to

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Doubtnut

3 days ago

` int _(0)^(pi/2) ((root(n)secx)/(root(n) ( secx+ root(n)"cosec"x)))dx` is equal to

` int _(0)^(pi/2) ((root(n)secx)/(root(n) ( secx+ root(n)"cosec"x)))dx` is equal to